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310=(3w-1)w
We move all terms to the left:
310-((3w-1)w)=0
We calculate terms in parentheses: -((3w-1)w), so:We get rid of parentheses
(3w-1)w
We multiply parentheses
3w^2-1w
Back to the equation:
-(3w^2-1w)
-3w^2+1w+310=0
We add all the numbers together, and all the variables
-3w^2+w+310=0
a = -3; b = 1; c = +310;
Δ = b2-4ac
Δ = 12-4·(-3)·310
Δ = 3721
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3721}=61$$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-61}{2*-3}=\frac{-62}{-6} =10+1/3 $$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+61}{2*-3}=\frac{60}{-6} =-10 $
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