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314r^2=314
We move all terms to the left:
314r^2-(314)=0
a = 314; b = 0; c = -314;
Δ = b2-4ac
Δ = 02-4·314·(-314)
Δ = 394384
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{394384}=628$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-628}{2*314}=\frac{-628}{628} =-1 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+628}{2*314}=\frac{628}{628} =1 $
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