31=(2x)+(3x-1)+(x+2)

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Solution for 31=(2x)+(3x-1)+(x+2) equation:



31=(2x)+(3x-1)+(x+2)
We move all terms to the left:
31-((2x)+(3x-1)+(x+2))=0
We calculate terms in parentheses: -(2x+(3x-1)+(x+2)), so:
2x+(3x-1)+(x+2)
We get rid of parentheses
2x+3x+x-1+2
We add all the numbers together, and all the variables
6x+1
Back to the equation:
-(6x+1)
We get rid of parentheses
-6x-1+31=0
We add all the numbers together, and all the variables
-6x+30=0
We move all terms containing x to the left, all other terms to the right
-6x=-30
x=-30/-6
x=+5

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