31=1/7c+22

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Solution for 31=1/7c+22 equation: 



31=1/7c+22

We move all terms to the left:

31-(1/7c+22)=0



Domain of the equation: 7c+22)!=0

c∈R



We get rid of parentheses

-1/7c-22+31=0

We multiply all the terms by the denominator


-22*7c+31*7c-1=0

Wy multiply elements

-154c+217c-1=0

We add all the numbers together, and all the variables

63c-1=0

We move all terms containing c to the left, all other terms to the right

63c=1

c=1/63

c=1/63

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