31=5(2c+7)

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Solution for 31=5(2c+7) equation: 



31=5(2c+7)

We move all terms to the left:

31-(5(2c+7))=0



We calculate terms in parentheses: -(5(2c+7)), so:

5(2c+7)

We multiply parentheses

10c+35

Back to the equation:

-(10c+35)



We get rid of parentheses

-10c-35+31=0

We add all the numbers together, and all the variables

-10c-4=0

We move all terms containing c to the left, all other terms to the right

-10c=4

c=4/-10

c=-2/5

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