31=5(b-2)

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Solution for 31=5(b-2) equation: 



31=5(b-2)

We move all terms to the left:

31-(5(b-2))=0



We calculate terms in parentheses: -(5(b-2)), so:

5(b-2)

We multiply parentheses

5b-10

Back to the equation:

-(5b-10)



We get rid of parentheses

-5b+10+31=0

We add all the numbers together, and all the variables

-5b+41=0

We move all terms containing b to the left, all other terms to the right

-5b=-41

b=-41/-5

b=8+1/5

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