31=6(1+2v)-5(-7v-5)

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Solution for 31=6(1+2v)-5(-7v-5) equation: 



31=6(1+2v)-5(-7v-5)

We move all terms to the left:

31-(6(1+2v)-5(-7v-5))=0

We add all the numbers together, and all the variables

-(6(2v+1)-5(-7v-5))+31=0



We calculate terms in parentheses: -(6(2v+1)-5(-7v-5)), so:

6(2v+1)-5(-7v-5)

We multiply parentheses

12v+35v+6+25

We add all the numbers together, and all the variables

47v+31

Back to the equation:

-(47v+31)



We get rid of parentheses

-47v-31+31=0

We add all the numbers together, and all the variables

-47v=0

v=0/-47

v=0

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