31x+5+13=34(-13+7x)-23(1+2x)

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Solution for 31x+5+13=34(-13+7x)-23(1+2x) equation: 



31x+5+13=34(-13+7x)-23(1+2x)

We move all terms to the left:

31x+5+13-(34(-13+7x)-23(1+2x))=0

We add all the numbers together, and all the variables

31x-(34(7x-13)-23(2x+1))+5+13=0

We add all the numbers together, and all the variables

31x-(34(7x-13)-23(2x+1))+18=0



We calculate terms in parentheses: -(34(7x-13)-23(2x+1)), so:

34(7x-13)-23(2x+1)

We multiply parentheses

238x-46x-442-23

We add all the numbers together, and all the variables

192x-465

Back to the equation:

-(192x-465)



We get rid of parentheses

31x-192x+465+18=0

We add all the numbers together, and all the variables

-161x+483=0

We move all terms containing x to the left, all other terms to the right

-161x=-483

x=-483/-161

x=+3

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