32(3x)-32(5)=32(7)

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Solution for 32(3x)-32(5)=32(7) equation: 



32(3x)-32(5)=32(7)

We move all terms to the left:

32(3x)-32(5)-(32(7))=0

determiningTheFunctionDomain
323x-325-327=0

We add all the numbers together, and all the variables

323x-652=0

We move all terms containing x to the left, all other terms to the right

323x=652

x=652/323

x=2+6/323

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