32(3x+63)=16x

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Solution for 32(3x+63)=16x equation: 



32(3x+63)=16x

We move all terms to the left:

32(3x+63)-(16x)=0

We add all the numbers together, and all the variables

-16x+32(3x+63)=0

We multiply parentheses

-16x+96x+2016=0

We add all the numbers together, and all the variables

80x+2016=0

We move all terms containing x to the left, all other terms to the right

80x=-2016

x=-2016/80

x=-25+1/5

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