32(3x-2)=12(x+1)

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Solution for 32(3x-2)=12(x+1) equation:



32(3x-2)=12(x+1)
We move all terms to the left:
32(3x-2)-(12(x+1))=0
We multiply parentheses
96x-(12(x+1))-64=0
We calculate terms in parentheses: -(12(x+1)), so:
12(x+1)
We multiply parentheses
12x+12
Back to the equation:
-(12x+12)
We get rid of parentheses
96x-12x-12-64=0
We add all the numbers together, and all the variables
84x-76=0
We move all terms containing x to the left, all other terms to the right
84x=76
x=76/84
x=19/21

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