32(4x+4)=12(8x+20)+4

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Solution for 32(4x+4)=12(8x+20)+4 equation:



32(4x+4)=12(8x+20)+4
We move all terms to the left:
32(4x+4)-(12(8x+20)+4)=0
We multiply parentheses
128x-(12(8x+20)+4)+128=0
We calculate terms in parentheses: -(12(8x+20)+4), so:
12(8x+20)+4
We multiply parentheses
96x+240+4
We add all the numbers together, and all the variables
96x+244
Back to the equation:
-(96x+244)
We get rid of parentheses
128x-96x-244+128=0
We add all the numbers together, and all the variables
32x-116=0
We move all terms containing x to the left, all other terms to the right
32x=116
x=116/32
x=3+5/8

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