32(4x+4)=12(8x+20)+4

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Solution for 32(4x+4)=12(8x+20)+4 equation: 



32(4x+4)=12(8x+20)+4

We move all terms to the left:

32(4x+4)-(12(8x+20)+4)=0

We multiply parentheses

128x-(12(8x+20)+4)+128=0



We calculate terms in parentheses: -(12(8x+20)+4), so:

12(8x+20)+4

We multiply parentheses

96x+240+4

We add all the numbers together, and all the variables

96x+244

Back to the equation:

-(96x+244)



We get rid of parentheses

128x-96x-244+128=0

We add all the numbers together, and all the variables

32x-116=0

We move all terms containing x to the left, all other terms to the right

32x=116

x=116/32

x=3+5/8

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