32(4x-7)=3x+16

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Solution for 32(4x-7)=3x+16 equation: 



32(4x-7)=3x+16

We move all terms to the left:

32(4x-7)-(3x+16)=0

We multiply parentheses

128x-(3x+16)-224=0

We get rid of parentheses

128x-3x-16-224=0

We add all the numbers together, and all the variables

125x-240=0

We move all terms containing x to the left, all other terms to the right

125x=240

x=240/125

x=1+23/25

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