32(9q+103)=27(7q+225)

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Solution for 32(9q+103)=27(7q+225) equation: 



32(9q+103)=27(7q+225)

We move all terms to the left:

32(9q+103)-(27(7q+225))=0

We multiply parentheses

288q-(27(7q+225))+3296=0



We calculate terms in parentheses: -(27(7q+225)), so:

27(7q+225)

We multiply parentheses

189q+6075

Back to the equation:

-(189q+6075)



We get rid of parentheses

288q-189q-6075+3296=0

We add all the numbers together, and all the variables

99q-2779=0

We move all terms containing q to the left, all other terms to the right

99q=2779

q=2779/99

q=28+7/99

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