32(x)=4(2x+1)

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Solution for 32(x)=4(2x+1) equation: 



32(x)=4(2x+1)

We move all terms to the left:

32(x)-(4(2x+1))=0



We calculate terms in parentheses: -(4(2x+1)), so:

4(2x+1)

We multiply parentheses

8x+4

Back to the equation:

-(8x+4)



We get rid of parentheses

32x-8x-4=0

We add all the numbers together, and all the variables

24x-4=0

We move all terms containing x to the left, all other terms to the right

24x=4

x=4/24

x=1/6

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