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32(x+1)8/3x+1=9
We move all terms to the left:
32(x+1)8/3x+1-(9)=0
Domain of the equation: 3x!=0We add all the numbers together, and all the variables
x!=0/3
x!=0
x∈R
32(x+1)8/3x-8=0
We multiply all the terms by the denominator
32(x+1)8-8*3x=0
We multiply parentheses
256x-8*3x+256=0
Wy multiply elements
256x-24x+256=0
We add all the numbers together, and all the variables
232x+256=0
We move all terms containing x to the left, all other terms to the right
232x=-256
x=-256/232
x=-1+3/29
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