32(x+1)=20(3x-2)

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Solution for 32(x+1)=20(3x-2) equation: 



32(x+1)=20(3x-2)

We move all terms to the left:

32(x+1)-(20(3x-2))=0

We multiply parentheses

32x-(20(3x-2))+32=0



We calculate terms in parentheses: -(20(3x-2)), so:

20(3x-2)

We multiply parentheses

60x-40

Back to the equation:

-(60x-40)



We get rid of parentheses

32x-60x+40+32=0

We add all the numbers together, and all the variables

-28x+72=0

We move all terms containing x to the left, all other terms to the right

-28x=-72

x=-72/-28

x=2+4/7

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