32(x+10)+29x+3(x+5)=945

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Solution for 32(x+10)+29x+3(x+5)=945 equation: 



32(x+10)+29x+3(x+5)=945

We move all terms to the left:

32(x+10)+29x+3(x+5)-(945)=0

We add all the numbers together, and all the variables

29x+32(x+10)+3(x+5)-945=0

We multiply parentheses

29x+32x+3x+320+15-945=0

We add all the numbers together, and all the variables

64x-610=0

We move all terms containing x to the left, all other terms to the right

64x=610

x=610/64

x=9+17/32

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