32(x+2)=10(x-1)

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Solution for 32(x+2)=10(x-1) equation: 



32(x+2)=10(x-1)

We move all terms to the left:

32(x+2)-(10(x-1))=0

We multiply parentheses

32x-(10(x-1))+64=0



We calculate terms in parentheses: -(10(x-1)), so:

10(x-1)

We multiply parentheses

10x-10

Back to the equation:

-(10x-10)



We get rid of parentheses

32x-10x+10+64=0

We add all the numbers together, and all the variables

22x+74=0

We move all terms containing x to the left, all other terms to the right

22x=-74

x=-74/22

x=-3+4/11

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