32(y+10)+29y+3(y+5)=945

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Solution for 32(y+10)+29y+3(y+5)=945 equation:



32(y+10)+29y+3(y+5)=945
We move all terms to the left:
32(y+10)+29y+3(y+5)-(945)=0
We add all the numbers together, and all the variables
29y+32(y+10)+3(y+5)-945=0
We multiply parentheses
29y+32y+3y+320+15-945=0
We add all the numbers together, and all the variables
64y-610=0
We move all terms containing y to the left, all other terms to the right
64y=610
y=610/64
y=9+17/32

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