32(y+2)=4(7y+8)

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Solution for 32(y+2)=4(7y+8) equation:


Simplifying
32(y + 2) = 4(7y + 8)

Reorder the terms:
32(2 + y) = 4(7y + 8)
(2 * 32 + y * 32) = 4(7y + 8)
(64 + 32y) = 4(7y + 8)

Reorder the terms:
64 + 32y = 4(8 + 7y)
64 + 32y = (8 * 4 + 7y * 4)
64 + 32y = (32 + 28y)

Solving
64 + 32y = 32 + 28y

Solving for variable 'y'.

Move all terms containing y to the left, all other terms to the right.

Add '-28y' to each side of the equation.
64 + 32y + -28y = 32 + 28y + -28y

Combine like terms: 32y + -28y = 4y
64 + 4y = 32 + 28y + -28y

Combine like terms: 28y + -28y = 0
64 + 4y = 32 + 0
64 + 4y = 32

Add '-64' to each side of the equation.
64 + -64 + 4y = 32 + -64

Combine like terms: 64 + -64 = 0
0 + 4y = 32 + -64
4y = 32 + -64

Combine like terms: 32 + -64 = -32
4y = -32

Divide each side by '4'.
y = -8

Simplifying
y = -8

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