32+3y2=16

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Solution for 32+3y2=16 equation: 



32+3y^2=16

We move all terms to the left:

32+3y^2-(16)=0

We add all the numbers together, and all the variables

3y^2+16=0

a = 3; b = 0; c = +16;
Δ = b2-4ac
Δ = 02-4·3·16
Δ = -192
Delta is less than zero, so there is no solution for the equation

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