32+4(c-1)=4(c+5)

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Solution for 32+4(c-1)=4(c+5) equation:


Simplifying
32 + 4(c + -1) = 4(c + 5)

Reorder the terms:
32 + 4(-1 + c) = 4(c + 5)
32 + (-1 * 4 + c * 4) = 4(c + 5)
32 + (-4 + 4c) = 4(c + 5)

Combine like terms: 32 + -4 = 28
28 + 4c = 4(c + 5)

Reorder the terms:
28 + 4c = 4(5 + c)
28 + 4c = (5 * 4 + c * 4)
28 + 4c = (20 + 4c)

Add '-4c' to each side of the equation.
28 + 4c + -4c = 20 + 4c + -4c

Combine like terms: 4c + -4c = 0
28 + 0 = 20 + 4c + -4c
28 = 20 + 4c + -4c

Combine like terms: 4c + -4c = 0
28 = 20 + 0
28 = 20

Solving
28 = 20

Couldn't find a variable to solve for.

This equation is invalid, the left and right sides are not equal, therefore there is no solution.

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