32+4c(c-1)=-(4c+5)

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Solution for 32+4c(c-1)=-(4c+5) equation: 



32+4c(c-1)=-(4c+5)

We move all terms to the left:

32+4c(c-1)-(-(4c+5))=0

We multiply parentheses

4c^2-4c-(-(4c+5))+32=0



We calculate terms in parentheses: -(-(4c+5)), so:

-(4c+5)

We get rid of parentheses

-4c-5

Back to the equation:

-(-4c-5)



We get rid of parentheses

4c^2-4c+4c+5+32=0

We add all the numbers together, and all the variables

4c^2+37=0

a = 4; b = 0; c = +37;
Δ = b2-4ac
Δ = 02-4·4·37
Δ = -592
Delta is less than zero, so there is no solution for the equation

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