32+5b=7b-4(2b+4)

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Solution for 32+5b=7b-4(2b+4) equation: 



32+5b=7b-4(2b+4)

We move all terms to the left:

32+5b-(7b-4(2b+4))=0



We calculate terms in parentheses: -(7b-4(2b+4)), so:

7b-4(2b+4)

We multiply parentheses

7b-8b-16

We add all the numbers together, and all the variables

-1b-16

Back to the equation:

-(-1b-16)



We get rid of parentheses

5b+1b+16+32=0

We add all the numbers together, and all the variables

6b+48=0

We move all terms containing b to the left, all other terms to the right

6b=-48

b=-48/6

b=-8

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