32+6n2=98n

Solution for 32+6n2=98n equation:

32+6n^2=98n

We move all terms to the left:

32+6n^2-(98n)=0

a = 6; b = -98; c = +32;
Δ = b2-4ac
Δ = -982-4·6·32
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-98)-94}{2*6}=\frac{4}{12}
=1/3
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-98)+94}{2*6}=\frac{192}{12}
=16
$