32+7x=2(1+4x)

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Solution for 32+7x=2(1+4x) equation: 



32+7x=2(1+4x)

We move all terms to the left:

32+7x-(2(1+4x))=0

We add all the numbers together, and all the variables

7x-(2(4x+1))+32=0



We calculate terms in parentheses: -(2(4x+1)), so:

2(4x+1)

We multiply parentheses

8x+2

Back to the equation:

-(8x+2)



We get rid of parentheses

7x-8x-2+32=0

We add all the numbers together, and all the variables

-1x+30=0

We move all terms containing x to the left, all other terms to the right

-x=-30

x=-30/-1

x=+30

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