32+98s=-6s2

Solution for 32+98s=-6s2 equation:

32+98s=-6s^2

We move all terms to the left:

32+98s-(-6s^2)=0

We get rid of parentheses

6s^2+98s+32=0

a = 6; b = 98; c = +32;
Δ = b2-4ac
Δ = 982-4·6·32
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{8836}=94$
$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-94}{2*6}=\frac{-192}{12}
=-16
$
$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+94}{2*6}=\frac{-4}{12}
=-1/3
$