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32+98s=-6s^2
We move all terms to the left:
32+98s-(-6s^2)=0
We get rid of parentheses
6s^2+98s+32=0
a = 6; b = 98; c = +32;
Δ = b2-4ac
Δ = 982-4·6·32
Δ = 8836
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{8836}=94$$s_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(98)-94}{2*6}=\frac{-192}{12} =-16 $$s_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(98)+94}{2*6}=\frac{-4}{12} =-1/3 $
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