32-(2c+4)=2(c+4)+c

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Solution for 32-(2c+4)=2(c+4)+c equation: 


Simplifying
32 + -1(2c + 4) = 2(c + 4) + c

Reorder the terms:
32 + -1(4 + 2c) = 2(c + 4) + c
32 + (4 * -1 + 2c * -1) = 2(c + 4) + c
32 + (-4 + -2c) = 2(c + 4) + c

Combine like terms: 32 + -4 = 28
28 + -2c = 2(c + 4) + c

Reorder the terms:
28 + -2c = 2(4 + c) + c
28 + -2c = (4 * 2 + c * 2) + c
28 + -2c = (8 + 2c) + c

Combine like terms: 2c + c = 3c
28 + -2c = 8 + 3c

Solving
28 + -2c = 8 + 3c

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '-3c' to each side of the equation.
28 + -2c + -3c = 8 + 3c + -3c

Combine like terms: -2c + -3c = -5c
28 + -5c = 8 + 3c + -3c

Combine like terms: 3c + -3c = 0
28 + -5c = 8 + 0
28 + -5c = 8

Add '-28' to each side of the equation.
28 + -28 + -5c = 8 + -28

Combine like terms: 28 + -28 = 0
0 + -5c = 8 + -28
-5c = 8 + -28

Combine like terms: 8 + -28 = -20
-5c = -20

Divide each side by '-5'.
c = 4

Simplifying
c = 4

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