32-(2c+4)=2(c+6)+c

Solution for 32-(2c+4)=2(c+6)+c equation:

32-(2c+4)=2(c+6)+c

We move all terms to the left:

32-(2c+4)-(2(c+6)+c)=0

We get rid of parentheses

-2c-(2(c+6)+c)-4+32=0


We calculate terms in parentheses: -(2(c+6)+c), so:

2(c+6)+c

We add all the numbers together, and all the variables

c+2(c+6)

We multiply parentheses

c+2c+12

We add all the numbers together, and all the variables

3c+12

Back to the equation:

-(3c+12)


We add all the numbers together, and all the variables

-2c-(3c+12)+28=0

We get rid of parentheses

-2c-3c-12+28=0

We add all the numbers together, and all the variables

-5c+16=0

We move all terms containing c to the left, all other terms to the right

-5c=-16

c=-16/-5

c=3+1/5