32-(3/8)y=(3/4)y+5

Solution for 32-(3/8)y=(3/4)y+5 equation:

32-(3/8)y=(3/4)y+5

We move all terms to the left:

32-(3/8)y-((3/4)y+5)=0


Domain of the equation: 8)y!=0

y!=0/1

y!=0

y∈R



Domain of the equation: 4)y+5)!=0

y!=0/1

y!=0

y∈R


We add all the numbers together, and all the variables

-(+3/8)y-((+3/4)y+5)+32=0

We multiply parentheses

-3y^2-((+3/4)y+5)+32=0

We multiply all the terms by the denominator


-3y^2*4)y+5)-((+32*4)y+5)+3=0

We add all the numbers together, and all the variables

-3y^2*4)y+5)-(128y+5)+3=0

Wy multiply elements

-12y^3=0

We do not support eypression: y^3