32-(5+c)=20

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Solution for 32-(5+c)=20 equation:



32-(5+c)=20
We move all terms to the left:
32-(5+c)-(20)=0
We add all the numbers together, and all the variables
-(c+5)+32-20=0
We add all the numbers together, and all the variables
-(c+5)+12=0
We get rid of parentheses
-c-5+12=0
We add all the numbers together, and all the variables
-1c+7=0
We move all terms containing c to the left, all other terms to the right
-c=-7
c=-7/-1
c=+7

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