32-2(6m+20)=-8(4-m)

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Solution for 32-2(6m+20)=-8(4-m) equation: 



32-2(6m+20)=-8(4-m)

We move all terms to the left:

32-2(6m+20)-(-8(4-m))=0

We add all the numbers together, and all the variables

-2(6m+20)-(-8(-1m+4))+32=0

We multiply parentheses

-12m-(-8(-1m+4))-40+32=0



We calculate terms in parentheses: -(-8(-1m+4)), so:

-8(-1m+4)

We multiply parentheses

8m-32

Back to the equation:

-(8m-32)



We add all the numbers together, and all the variables

-12m-(8m-32)-8=0

We get rid of parentheses

-12m-8m+32-8=0

We add all the numbers together, and all the variables

-20m+24=0

We move all terms containing m to the left, all other terms to the right

-20m=-24

m=-24/-20

m=1+1/5

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