32-7v=6(-v+4)-3v

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Solution for 32-7v=6(-v+4)-3v equation: 



32-7v=6(-v+4)-3v

We move all terms to the left:

32-7v-(6(-v+4)-3v)=0

We add all the numbers together, and all the variables

-7v-(6(-1v+4)-3v)+32=0



We calculate terms in parentheses: -(6(-1v+4)-3v), so:

6(-1v+4)-3v

We add all the numbers together, and all the variables

-3v+6(-1v+4)

We multiply parentheses

-3v-6v+24

We add all the numbers together, and all the variables

-9v+24

Back to the equation:

-(-9v+24)



We get rid of parentheses

-7v+9v-24+32=0

We add all the numbers together, and all the variables

2v+8=0

We move all terms containing v to the left, all other terms to the right

2v=-8

v=-8/2

v=-4

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