32-b=-7(b-2)

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Solution for 32-b=-7(b-2) equation: 



32-b=-7(b-2)

We move all terms to the left:

32-b-(-7(b-2))=0

We add all the numbers together, and all the variables

-1b-(-7(b-2))+32=0



We calculate terms in parentheses: -(-7(b-2)), so:

-7(b-2)

We multiply parentheses

-7b+14

Back to the equation:

-(-7b+14)



We get rid of parentheses

-1b+7b-14+32=0

We add all the numbers together, and all the variables

6b+18=0

We move all terms containing b to the left, all other terms to the right

6b=-18

b=-18/6

b=-3

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