32/2x=5

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Solution for 32/2x=5 equation: 



32/2x=5

We move all terms to the left:

32/2x-(5)=0



Domain of the equation: 2x!=0

x!=0/2

x!=0

x∈R



We multiply all the terms by the denominator


-5*2x+32=0

Wy multiply elements

-10x+32=0

We move all terms containing x to the left, all other terms to the right

-10x=-32

x=-32/-10

x=3+1/5

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