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32/3k+1/3(42=48k)
We move all terms to the left:
32/3k+1/3(42-(48k))=0
Domain of the equation: 3k!=0
k!=0/3
k!=0
k∈R
Domain of the equation: 3(42-48k)!=0We add all the numbers together, and all the variables
k∈R
32/3k+1/3(-48k+42)=0
We calculate fractions
(96k(-)/(9k^2(-)+3k/(9k^2(-)=0
We calculate terms in parentheses: +(96k(-)/(9k^2(-)+3k/(9k^2(-), so:
96k(-)/(9k^2(-)+3k/(9k^2(-
We can not solve this equation
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