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32/d=12-d
We move all terms to the left:
32/d-(12-d)=0
Domain of the equation: d!=0We add all the numbers together, and all the variables
d∈R
32/d-(-1d+12)=0
We get rid of parentheses
32/d+1d-12=0
We multiply all the terms by the denominator
1d*d-12*d+32=0
We add all the numbers together, and all the variables
-12d+1d*d+32=0
Wy multiply elements
d^2-12d+32=0
a = 1; b = -12; c = +32;
Δ = b2-4ac
Δ = -122-4·1·32
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$d_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-12)-4}{2*1}=\frac{8}{2} =4 $$d_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-12)+4}{2*1}=\frac{16}{2} =8 $
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