32/n=2n-12

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Solution for 32/n=2n-12 equation: 


D( n )

n = 0

n = 0

n = 0

n in (-oo:0) U (0:+oo)

32/n = 2*n-12 // - 2*n-12

32/n-(2*n)+12 = 0

32/n-2*n+12 = 0

32*n^-1-2*n^1+12*n^0 = 0

(12*n^1-2*n^2+32*n^0)/(n^1) = 0 // * n^2

n^1*(12*n^1-2*n^2+32*n^0) = 0

n^1

12*n-2*n^2+32 = 0

12*n-2*n^2+32 = 0

DELTA = 12^2-(-2*4*32)

DELTA = 400

DELTA > 0

n = (400^(1/2)-12)/(-2*2) or n = (-400^(1/2)-12)/(-2*2)

n = -2 or n = 8

n in { -2, 8} 

n in { -2, 8 }

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