320=1/3x+(x-30)

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Solution for 320=1/3x+(x-30) equation: 



320=1/3x+(x-30)

We move all terms to the left:

320-(1/3x+(x-30))=0



Domain of the equation: 3x+(x-30))!=0

x∈R



We multiply all the terms by the denominator


-(1+320*3x+(x-30))=0



We calculate terms in parentheses: -(1+320*3x+(x-30)), so:

1+320*3x+(x-30)

determiningTheFunctionDomain
320*3x+(x-30)+1

Wy multiply elements

960x+(x-30)+1

We get rid of parentheses

960x+x-30+1

We add all the numbers together, and all the variables

961x-29

Back to the equation:

-(961x-29)



We get rid of parentheses

-961x+29=0

We move all terms containing x to the left, all other terms to the right

-961x=-29

x=-29/-961

x=29/961

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