320=2x(x-12)

Solution for 320=2x(x-12) equation:

320=2x(x-12)

We move all terms to the left:

320-(2x(x-12))=0


We calculate terms in parentheses: -(2x(x-12)), so:

2x(x-12)

We multiply parentheses

2x^2-24x

Back to the equation:

-(2x^2-24x)


We get rid of parentheses

-2x^2+24x+320=0

a = -2; b = 24; c = +320;
Δ = b2-4ac
Δ = 242-4·(-2)·320
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(24)-56}{2*-2}=\frac{-80}{-4}
=+20
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(24)+56}{2*-2}=\frac{32}{-4}
=-8
$