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320=x*x
We move all terms to the left:
320-(x*x)=0
We add all the numbers together, and all the variables
-(+x*x)+320=0
We get rid of parentheses
-x*x+320=0
Wy multiply elements
-1x^2+320=0
a = -1; b = 0; c = +320;
Δ = b2-4ac
Δ = 02-4·(-1)·320
Δ = 1280
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{1280}=\sqrt{256*5}=\sqrt{256}*\sqrt{5}=16\sqrt{5}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{5}}{2*-1}=\frac{0-16\sqrt{5}}{-2} =-\frac{16\sqrt{5}}{-2} =-\frac{8\sqrt{5}}{-1} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{5}}{2*-1}=\frac{0+16\sqrt{5}}{-2} =\frac{16\sqrt{5}}{-2} =\frac{8\sqrt{5}}{-1} $
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