32148x(3x-5)=17

Solution for 32148x(3x-5)=17 equation:

32148x(3x-5)=17

We move all terms to the left:

32148x(3x-5)-(17)=0

We multiply parentheses

96444x^2-160740x-17=0

a = 96444; b = -160740; c = -17;
Δ = b2-4ac
Δ = -1607402-4·96444·(-17)
Δ = 25843905792
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{25843905792}=\sqrt{2304*11216973}=\sqrt{2304}*\sqrt{11216973}=48\sqrt{11216973}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-160740)-48\sqrt{11216973}}{2*96444}=\frac{160740-48\sqrt{11216973}}{192888}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-160740)+48\sqrt{11216973}}{2*96444}=\frac{160740+48\sqrt{11216973}}{192888}
$