324=n2

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Solution for 324=n2 equation:



324=n2
We move all terms to the left:
324-(n2)=0
We add all the numbers together, and all the variables
-1n^2+324=0
a = -1; b = 0; c = +324;
Δ = b2-4ac
Δ = 02-4·(-1)·324
Δ = 1296
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1296}=36$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-36}{2*-1}=\frac{-36}{-2} =+18 $
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+36}{2*-1}=\frac{36}{-2} =-18 $

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