324q2+36q+1=0

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Solution for 324q2+36q+1=0 equation: 



324q^2+36q+1=0

a = 324; b = 36; c = +1;
Δ = b2-4ac
Δ = 362-4·324·1
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$q=\frac{-b}{2a}=\frac{-36}{648}=-1/18$

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