325/28=6/7b+3/4b+10

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Solution for 325/28=6/7b+3/4b+10 equation: 


b in (-oo:+oo)

325/28 = (6/7)*b+(3/4)*b+10 // - (6/7)*b+(3/4)*b+10

325/28-((6/7)*b)-((3/4)*b)-10 = 0

(-6/7)*b+(-3/4)*b+325/28-10 = 0

45/28-45/28*b = 0 // - 45/28

-45/28*b = -45/28 // : -45/28

b = -45/28/(-45/28)

b = 1

b = 1

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