325=n(n+1)/2

Solution for 325=n(n+1)/2 equation:

325=n(n+1)/2

We move all terms to the left:

325-(n(n+1)/2)=0

We multiply all the terms by the denominator


-(n(n+1)+325*2)=0


We calculate terms in parentheses: -(n(n+1)+325*2), so:

n(n+1)+325*2

We add all the numbers together, and all the variables

n(n+1)+650

We multiply parentheses

n^2+n+650

Back to the equation:

-(n^2+n+650)


We get rid of parentheses

-n^2-n-650=0

We add all the numbers together, and all the variables

-1n^2-1n-650=0

a = -1; b = -1; c = -650;
Δ = b2-4ac
Δ = -12-4·(-1)·(-650)
Δ = -2599
Delta is less than zero, so there is no solution for the equation