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326+(14+2x)(24+2x)=816
We move all terms to the left:
326+(14+2x)(24+2x)-(816)=0
We add all the numbers together, and all the variables
(2x+14)(2x+24)+326-816=0
We add all the numbers together, and all the variables
(2x+14)(2x+24)-490=0
We multiply parentheses ..
(+4x^2+48x+28x+336)-490=0
We get rid of parentheses
4x^2+48x+28x+336-490=0
We add all the numbers together, and all the variables
4x^2+76x-154=0
a = 4; b = 76; c = -154;
Δ = b2-4ac
Δ = 762-4·4·(-154)
Δ = 8240
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{8240}=\sqrt{16*515}=\sqrt{16}*\sqrt{515}=4\sqrt{515}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(76)-4\sqrt{515}}{2*4}=\frac{-76-4\sqrt{515}}{8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(76)+4\sqrt{515}}{2*4}=\frac{-76+4\sqrt{515}}{8} $
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