32=(-2)-5z

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Solution for 32=(-2)-5z equation: 



32=(-2)-5z

We move all terms to the left:

32-((-2)-5z)=0



We calculate terms in parentheses: -((-2)-5z), so:

(-2)-5z

determiningTheFunctionDomain
-5z+(-2)

We add all the numbers together, and all the variables

-5z-2

Back to the equation:

-(-5z-2)



We get rid of parentheses

5z+2+32=0

We add all the numbers together, and all the variables

5z+34=0

We move all terms containing z to the left, all other terms to the right

5z=-34

z=-34/5

z=-6+4/5

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