32=(y)(y+4)

Solution for 32=(y)(y+4) equation:

Simplifying
32 = (y)(y + 4)

Reorder the terms:
32 = y(4 + y)
32 = (4 * y + y * y)
32 = (4y + y2)

Solving
32 = 4y + y2

Solving for variable 'y'.

Reorder the terms:
32 + -4y + -1y2 = 4y + -4y + y2 + -1y2

Combine like terms: 4y + -4y = 0
32 + -4y + -1y2 = 0 + y2 + -1y2
32 + -4y + -1y2 = y2 + -1y2

Combine like terms: y2 + -1y2 = 0
32 + -4y + -1y2 = 0

Factor a trinomial.
(4 + -1y)(8 + y) = 0

Subproblem 1
Set the factor '(4 + -1y)' equal to zero and attempt to solve:

Simplifying
4 + -1y = 0

Solving
4 + -1y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-4' to each side of the equation.
4 + -4 + -1y = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -1y = 0 + -4
-1y = 0 + -4

Combine like terms: 0 + -4 = -4
-1y = -4

Divide each side by '-1'.
y = 4

Simplifying
y = 4
Subproblem 2
Set the factor '(8 + y)' equal to zero and attempt to solve:

Simplifying
8 + y = 0

Solving
8 + y = 0

Move all terms containing y to the left, all other terms to the right.

Add '-8' to each side of the equation.
8 + -8 + y = 0 + -8

Combine like terms: 8 + -8 = 0
0 + y = 0 + -8
y = 0 + -8

Combine like terms: 0 + -8 = -8
y = -8

Simplifying
y = -8
Solution
y = {4, -8}